Physics · Chapter 2: Physical Quantities and Measurement

Screw Gauge

Parts of a micrometer screw gauge, pitch and least count 0.01 mm, taking a reading, the ratchet and zero error.

Taught in Class 9Class 11O LevelA Level

Key termRememberExampleWatch out

01Concept

To measure the thickness of a wire, a sheet of paper or a hair, we need an even more precise instrument: the screw gauge (micrometer screw gauge). Its least count is 0.01 mm, ten times smaller than vernier callipers.

A screw gauge. Turning the thimble moves the spindle towards the anvil.

Parts

  • U-shaped frame that holds everything.
  • Anvil: the fixed stud. Spindle: the moving rod. The object is held between them.
  • Sleeve with the main (linear) scale in millimetres along a reference line.
  • Thimble with the circular scale, usually 100 (or 50) equal divisions.
  • Ratchet: turns the thimble but slips once the object is held lightly, so you do not press too hard.

Pitch and least count

The pitch is the distance the spindle moves forward in one complete turn of the thimble. In most school screw gauges the pitch is 1 mm with 100 circular divisions, or 0.5 mm with 50 divisions.

Least count = pitch ÷ number of divisions on the circular scale = 1 mm ÷ 100 = 0.01 mm

Taking a reading

  1. Turn the ratchet until the object is held gently between the anvil and spindle.
  2. Read the main scale reading (MSR): the last mark visible on the sleeve. 5 mm
  3. Read the circular scale division that lines up with the reference line. 38
  4. Circular scale reading = 38 × 0.01 = 0.38 mm
  5. Total = MSR + circular scale reading = 5 + 0.38 = 5.38 mm

Zero error

When the anvil and spindle touch, the zero of the circular scale should be on the reference line. If not, there is a zero error.

Positive zero errorNegative zero error
Circular scale zero (jaws closed)Below the reference lineAbove the reference line
EffectReadings too largeReadings too small

Corrected reading = observed reading − zero error, exactly as for vernier callipers.

02Virtual Lab

Try this topic for yourself in the virtual lab. It opens on its own page with steps, tasks and questions.

03Key Formulas

Least count of a screw gauge

LC=pitchnumber of circular divisions\text{LC} = \frac{\text{pitch}}{\text{number of circular divisions}}

1 mm ÷ 100 = 0.01 mm, or 0.5 mm ÷ 50 = 0.01 mm.

Screw gauge reading

reading=MSR+(n×LC)\text{reading} = \text{MSR} + (n \times \text{LC})
  • nn = circular scale division on the reference line

04Real World Examples

Electricians

The thickness of copper wire decides how much current it can safely carry. Wire factories check diameters with micrometer screw gauges.

Paper and plastic

Paper mills and plastic-bag factories in Pakistan measure sheet thickness in microns (µm) with micrometers.

Engine parts

Engine pistons and crankshafts are measured with micrometers to 0.01 mm, because a small difference can ruin the engine.

05Practice Questions

Try to answer in your own words first, then open the model answer.

Short questions

Q1.Define pitch of a screw gauge.Show answer

Answer

Pitch is the distance moved by the spindle in one complete rotation of the thimble.

Q2.Find the least count of a screw gauge with a pitch of 0.5 mm and 50 circular divisions.Show answer

Answer

  • LC = pitch ÷ number of circular divisions
  • = 0.5 mm ÷ 50
  • = 0.01 mm
Q3.The main scale reading is 3 mm and the 46th circular division is on the reference line. Find the reading (LC = 0.01 mm).Show answer

Answer

  • Circular reading = 46 × 0.01 = 0.46 mm
  • Total = 3 + 0.46 = 3.46 mm
Q4.What is the use of the ratchet?Show answer

Answer

The ratchet slips when the object is held with the right pressure, so the object is not squeezed and the screw is not damaged. This gives the same pressure every time.

Q5.A screw gauge has a zero error of +0.03 mm. A wire reads 1.27 mm. Find its true diameter.Show answer

Answer

  • Corrected = 1.27 − 0.03
  • = 1.24 mm

Long questions

Q6.Describe a screw gauge and explain how you would use it to find the diameter of a wire.Show answer

Answer

  1. Find the pitch (e.g. 1 mm) and count the circular divisions (e.g. 100). LC = 1 ÷ 100 = 0.01 mm.
  2. Close the gauge with the ratchet and note the zero error with its sign.
  3. Place the wire between the anvil and spindle and turn the ratchet until it clicks.
  4. Read the main scale: e.g. 0 mm (or 0.5 mm if a half-mark is visible).
  5. Read the circular scale division on the reference line: e.g. 52 → 0.52 mm.
  6. Observed = MSR + circular reading = 0.52 mm.
  7. Corrected = observed − zero error.
  8. Repeat at three places along the wire, in two directions, and take the mean.

06Quiz

Question 1 of 8
The least count of a common screw gauge is: